A spring with spring constant k = 100 N/m is compressed by x = 0.2 m. What is the potential energy stored in the spring?

Prepare for the MIAT Physics Test. Access flashcards and practice multiple-choice questions with detailed explanations. Maximize your readiness!

Multiple Choice

A spring with spring constant k = 100 N/m is compressed by x = 0.2 m. What is the potential energy stored in the spring?

Explanation:
The energy stored in a spring when it is compressed or stretched comes from the work done to move it from its rest length. This energy is U = 1/2 k x^2, where k is the spring constant and x is the displacement from equilibrium. Here, k = 100 N/m and the compression is x = 0.2 m. Plugging in: U = (1/2) × 100 × (0.2)^2 = 50 × 0.04 = 2 J. So the spring stores 2 joules of potential energy. The 1 J option would come from misapplying the formula (missing the 1/2 factor). The energy grows with the square of the displacement, so doubling the compression would quadruple the energy.

The energy stored in a spring when it is compressed or stretched comes from the work done to move it from its rest length. This energy is U = 1/2 k x^2, where k is the spring constant and x is the displacement from equilibrium.

Here, k = 100 N/m and the compression is x = 0.2 m. Plugging in:

U = (1/2) × 100 × (0.2)^2 = 50 × 0.04 = 2 J.

So the spring stores 2 joules of potential energy. The 1 J option would come from misapplying the formula (missing the 1/2 factor). The energy grows with the square of the displacement, so doubling the compression would quadruple the energy.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy